10x^2-20x-240=0

Solution for 10x^2-20x-240=0 equation:

10x^2-20x-240=0

a = 10; b = -20; c = -240;
Δ = b2-4ac
Δ = -202-4·10·(-240)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-100}{2*10}=\frac{-80}{20}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+100}{2*10}=\frac{120}{20}
=6
$